Question
Two numbers are in the ratio 5:7. The product of their
H.C.F. and L.C.M. is 5040. The sum of the numbers is:Solution
Let the numbers be 5x and 7x respectively. First number × second number = HCF × LCM => 5x × 7x = 5040 => x2 = [5040/(5×7)] = 144 => x = √144 = 12 Sum of the numbers = 5x + 7x = 12x = 12 × 12 = 144
The least number which when divided by 6, 7, 10, 13, and 15 leaves the same remainder 5 in each case, is:
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