Question
The least number which when divided by 6, 7, 10, 13, and
15 leaves the same remainder 5 in each case, is:Solution
 Given Numbers: 6, 7, 10, 13, 15
 LCM of given numbers = 2730
 Add the remainder (5) to the LCM: 2730 + 5 = 2735
Evaluate (998)3 without multiplying directly.
If (a2 + 1/a2) = 18, then find the value of (a3 - 1/a3).
If x ,y,z are three integers such that x +y = 8,y +z =13 and z +x =17,then the value of x2 /yz  is:
If x + y + z = 20, x² + Y² + z² = 160 and x z = y², then find the value of x z?
- If (x + y + z) = 14 and (xy + yz + zx) = 50, then find the value of (x² + y² + z²).
- Suppose [a + (1/16a)] = 3, then the value of [16a³ + (1/256a³)] is:
- 42.5% of 20% of 960 = x + 18.4, then find the sum of the squares of each digit in 'x'.
If x + 1/x = 3, find the value of x³ + 1/x³.
If x – 1/x = 9, then x3 – 1/x3 is:
