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Let the two numbers be '5h' and '12h', where 'h' is the HCF of the two given numbers.
Product of two numbers = (Product of LCM and HCF) of the given two numbers
5h X 12h = h X 1440
Or, 60h = 1440
So, 'h' = (1440/60) = 24
Therefore, the required sum = 5h + 12h = 17h = 17 X 24 = 408