Question
If total number of factors of 2,520 is 'y', then find
the value of (y - 4)(y + 6).Solution
Factors of 2,520 = 2³ × 3² × 5¹ × 7¹ So, total number of factors = (3 + 1)(2 + 1)(1 + 1)(1 + 1) = 4 × 3 × 2 × 2 = 48 y = 48 Required value = (y - 4)(y + 6) = (48 - 4)(48 + 6) = 44 × 54 = 2376.
The product of two numbers is 2880 and their GCD is 24. What is the LCM?
What should be the minimum number of chocolates so that when distributed among 3,4,5,6 and 7 children, 1,2,3,4 and 5 chocolates are left respectively?
Two numbers are in the ratio 2:7. The product of their H.C.F. and L.C.M. is 5054. The sum of the numbers is:
- The LCM and HCF of two integers are 540 and 12 respectively. If one of the integers is 90, find the second integer.
If the highest common factor of two numbers is 12, then which of the following may be the least common multiple of the numbers?
Determine the LCM of (8/35) and (24/5).
Find the difference between sum of digits of LCM and HCF of 32, 48 and 80.
Determine the HCF of 150 and 1350.
The L.C.M of a² – 2a – 3 and a³ + a² + a + 1 is
The product of two numbers is 132 and their highest common factor is 6. What is the least common multiple of these numbers?
