Question
What will be the greatest common divisor (GC
- D of (x² - 11x + 30) and (x² - 9x + 20).
Solution
(x² - 11x + 30) = x² - 5x - 6x + 30 = x(x - 5) - 6(x - 5) = (x - 5)(x - 6) x² - 9x + 20 = x² - 5x - 4x + 20 = x(x - 5) - 4(x - 5) = (x - 5)(x - 4) So, required GCD = (x - 5) Hence, option c.
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