Question
The smallest number which when divided by 28 and 32
leaves remainder 12 and 16 respectively is:Solution
The number = LCM (28, 32) â k, (where k = 28 â 12 = 32 â 16 = 16) LCM of 28 and 32 = 224 Subtract the common difference from 224, Required number will be = 224 - 16 = 208
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