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    Question

    The smallest number which when divided by 24 and 32

    leaves remainder 10 and 18 respectively is:
    A 35 Correct Answer Incorrect Answer
    B 82 Correct Answer Incorrect Answer
    C 61 Correct Answer Incorrect Answer
    D 93 Correct Answer Incorrect Answer

    Solution

    The number = LCM (24, 32) – k, (where k = 24 – 10 = 32 – 18 = 14) LCM of 24 and 32 = 96 Subtract the common difference from 96, Required number will be = 96 - 14 = 82

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