Question
The smallest number which when divided by 24 and 32
leaves remainder 10 and 18 respectively is:Solution
The number = LCM (24, 32) – k, (where k = 24 – 10 = 32 – 18 = 14) LCM of 24 and 32 = 96 Subtract the common difference from 96, Required number will be = 96 - 14 = 82
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