Question
A, B and C start running around a circular track and
complete one round in 10, 15 and 25 seconds respectively. In how many seconds will the three meet again at the starting point if they all have started running at the same time?Solution
As A, B and C complete one round in 10, 15 and 25 seconds respectively, they will be able to meet at the starting point only if we get a common multiple of 10, 15 and 25. To meet for the second time, we need to calculate LCM. LCM (10,15,25) = 150 ∴ They will meet again in 150 seconds.
The ratio of age of A and his son is 5:2. If the difference of their ages 4 year ago is 21, then find the sum of ages of A and his son 9 year hence?
A’s age is 160% of what he was 4 years ago, But 80% of what it will be after 4 years. What is his present age?
The ratio of age of ‘B’ after 6 years from now and age of ‘C’ 8 years ago from now is 7:4, respectively. The present age of ‘C’ is 30% of th...
Shalini is younger than Rashi by 3 years. If the ratio of Shalini and Rashi ages is 9:10 respectively, then find the age of Shalini.
A is younger than B by 4 years. If the ratio of A and B ages is 9:10 respectively, then find the age of A.
Six years ago, the ratio of ages of Alok and Ravi was 7:9, respectively. Eight years hence, the ratio of ages of Rohan and Ravi will be 5:6, respectivel...
Currently, Person 'A' is 42 years old. Person 'B' is 6 years younger than 'A'. Three years ago, the age of 'C' was 25% less than what 'B' is right now. ...
The sum of the present ages of Tina and her father is 50 years. Tina's father is 4 years older than her mother, and two years ago, Tina's mother's age w...
The ratio of age of A and his son is 10:3. If the difference of their ages 8 year ago is 28, then find the sum of ages of A and his son 12 year hence.
A is 2 years older than B while C is 3 years younger than B. The ratio of age of A, 5 years hence and age of B, 4 years ago is 5:4. What was age of C, 1...
Relevant for Exams:
