Question
What is the greatestĀ 4 digitsĀ number which when
added toĀ 5231, makes the sum exactly divisible by 12, 15, 27, 32, andĀ 40 ?Solution
Find L.C.M of 12, 15, 27, 32, 40, which is 4320. The Greatest number is determined by multiplying 4320 by 3 and subtracting 5231 from it 4320 is the smallest number which is completely divisible by the given numbers. And we have to find the largest 4 digit number, so to reach the bigger number we will multiply it by 3 and then subtract 5231 from it. The greatest number of 4 digitsĀ = 4320 Ć 3 - 5231. Ā Ā = 12960 - 5231 = 7729.
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