Question
What is the greatest 4 digits number which when added to 5231, makes the sum exactly divisible by 12, 15, 27, 32, and 40 ?
Solution
Find L.C.M of 12, 15, 27, 32, 40, which is 4320. The Greatest number is determined by multiplying 4320 by 3 and subtracting 5231 from it 4320 is the smallest number which is completely divisible by the given numbers. And we have to find the largest 4 digit number, so to reach the bigger number we will multiply it by 3 and then subtract 5231 from it. The greatest number of 4 digits = 4320 × 3 - 5231.   = 12960 - 5231 = 7729.
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