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      Question

      What is the greatestĀ  4 digitsĀ  number which when

      added toĀ  5231, makes the sum exactly divisible by 12, 15, 27, 32, andĀ  40 ?
      A 4320 Correct Answer Incorrect Answer
      B 7729 Correct Answer Incorrect Answer
      C 8640 Correct Answer Incorrect Answer
      D 2160 Correct Answer Incorrect Answer

      Solution

      Find L.C.M of 12, 15, 27, 32, 40, which is 4320. The Greatest number is determined by multiplying 4320 by 3 and subtracting 5231 from it 4320 is the smallest number which is completely divisible by the given numbers. And we have to find the largest 4 digit number, so to reach the bigger number we will multiply it by 3 and then subtract 5231 from it. The greatest number of 4 digitsĀ = 4320 Ɨ 3 - 5231. Ā Ā = 12960 - 5231 = 7729.

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