Question
The smallest number which when divided by 25 and 30
leaves remainder 10 and 15 respectively is:Solution
The number = LCM (25, 30) – k, (where k = 25 – 10 = 30 – 15 = 15) LCM of 25 and 30 = 150 Subtract the common difference from 150, Required number will be = 150 - 15 = 135
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