Question
The greatest number of four digits which when divided by
8, 10, 12 leave remainders 5, 7, 9 respectively is:Solution
The difference between divisor and the corresponding remainder is equal (i.e 3). LCM of 8, 10 and 12 = 120 Largest 4-digit number = 9999 After dividing 9999 by 120 we will get the remainder as 39. Therefore, the number divisible by 120 = 9999 – 39 = 9960 If 3 is subtracted from the number 9960 the resulting number will follow the condition in the question and that number is 9957.
More HCF and LCM Questions
15, 30, 30, 20, 10, 8
140Â Â Â 150Â Â Â 175Â Â Â Â 185Â Â Â Â 210Â Â Â Â Â 225Â Â Â Â Â
...66, 220, 384, 543, 702, 861
Find the wrong number in the given number series.
3, 9, 27, 81, 162, 243
- Find the wrong number in the given number series.
12, 16, 25, 50, 99, 200 16, 27, 44, 63, 98, 139
Find the wrong number in the given number series.
8.6, 11.3, 16.7, 24.2, 35.6, 49.1
11, 12, 20, 58, 234, 1168
74, 79, 86.5, 101.5, 109, 124, 141.5
- Find the wrong number in the given number series.
8, 16, 32, 70, 128, 256
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