Question
The greatest number of four digits which when divided by
8, 10, 12 leave remainders 5, 7, 9 respectively is:Solution
The difference between divisor and the corresponding remainder is equal (i.e 3). LCM of 8, 10 and 12 = 120 Largest 4-digit number = 9999 After dividing 9999 by 120 we will get the remainder as 39. Therefore, the number divisible by 120 = 9999 – 39 = 9960 If 3 is subtracted from the number 9960 the resulting number will follow the condition in the question and that number is 9957.
The LCM of two numbers is 4 times of their HCF. The sum of LCM and HCF is 320. If one of the number is 256, then the other number is:
Calculate the Least Common Multiple (L.C.M) of 144 and 180.
HCF of two numbers is 12 and their LCM is 924. If one number is 132, find the other.
- The product of two positive integers is 1400. If their HCF is 5 and their sum is 75, then find the difference between the numbers.
The LCM of two numbers is 720 while their HCF is 12. If one of the numbers is 120, then the other number is:
- Find the least common multiple of (18/27), (24/36), and (30/45).
Three numbers a, b and c are co-prime to each other such that ab = 221 and bc = 247. Find the value of (a + b + c).
The ratio of two numbers is 9:12 and their LCM is 324. The numbers are:
Find the HCF of 240, 280 and 560.
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