Question

    Find the area of triangle having sides 28 m, 45 m, and

    53 m.
    A 630 cm² Correct Answer Incorrect Answer
    B 330 cm² Correct Answer Incorrect Answer
    C 546 cm² Correct Answer Incorrect Answer
    D 210 cm² Correct Answer Incorrect Answer

    Solution

    As sides 28, 45 & 53 is a Pythagoras triplet means 282 + 452 = 532 ; this is a right angle triangle. So area of this triangle = 1/2 × base × height = (1/2) × 28 × 45 = 630 cm 2

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