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In ∆ PQS ∠QPS + ∠PQS + ∠PSQ = 180° ∠QPS + 58° + 90° = 180° ∠QPS = 32°
∠QCR = 2∠QPR (∠QCR)/2 = ∠QPR 140/2 = ∠QPS + ∠RPS 70° = 32° + ∠RPS ∠RPS = 38°
Without stopping the speed of the train is 125 kmph, with stopping the speed of the train is 75 kmph.Find the stop time of the train?
A man running at the speed of 5 kmph was over taken by the train moving with the speed of 77 kmph in 22 seconds. Find the length of train.
A train passes 150 m long platform in 10 seconds and a man standing on the platform in 8 seconds. Find the speed of the train?
A train 480 metres long is running at a speed of 54 km/hr. If it crosses a tunnel in 1 minute, then the length of the tunnel (in meters) is: