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Question

In ∆ABC, AB = 5cm, BC = 6cm and AC = 10cm then find out the value of cos A?

Q: In ∆ABC, AB = 5cm, BC = 6cm and AC = 10cm then find out the value of cos A?

cos A = (b 2 +c 2 - a 2 )/2bc = (10 2 +5 2 -6 2 )/(2×10×5) = 89/100

A 73/100

B 65/100

C 89/100

D 92/100

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Question

In ∆ABC, AB = 5cm, BC = 6cm and AC = 10cm then find out the value of cos A?

Solution

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