Question
In triangle ABC, the sides are AB = 13 cm, BC = 14 cm, and CA = 15 cm. What is the length of the altitude from vertex A to side BC?
Solution
ATQ, Sides: 13, 14, 15. Semiperimeter s = (13 + 14 + 15)/2 = 42/2 = 21. Area by Heron’s formula: Area = √[s(s − a)(s − b)(s − c)] = √[21·(21 − 13)·(21 − 14)·(21 − 15)] = √[21·8·7·6] = √7056 = 84 cm². Let h be the altitude from A to BC (which is 14 cm). Area = ½ × BC × h ⇒ 84 = ½ × 14 × h 84 = 7h ⇒ h = 12 cm.
More Geometry Questions
- Angles of a triangle are in the ratio 1 : 2 : 3. Find the measure of the largest angle.
- ABCD is a square. P, Q, R and S are points on the sides AB, BC, CD and DA respectively such that AP = BQ = CR = DS. Angle SPQ equal to ?
- If O is circumcentre of acute angled triangle ABC, if ∠ BOC = 60˚ then ∠BAC = ?
- Question 4
- If G is the centroid and AD, BE, CF are three medians of ∆ABC with area 78 cm 2 , then the area of ∆BGF is?
- If the area of ∆ ABC is 33 cm2 & G is the centroid of ∆ ABC.then the area of the ∆ BGC?
- Angles of a triangle are in the ratio 2 : 3 : 7. Find the sum of the smallest and largest angle of the triangle.
- Find out the circumference of a sector whose radius is 7 cm and it makes the angle of 45° at the centre?
- In the given figure, two identical circles of radius 4 cm touch each other. A and B are the centres of the two circles. If RQ is a tangent to the circle, t...
- In a circle, two chords of lengths p and q subtend the angles of 60° and 90° at the center respectively. Which of the following is correct in this scenario...