Question
In a circle, two radii OA and OB form a central angle of 120°. If the length of chord AB is 10 cm, what is the radius of the circle (in cm)?
Solution
ATQ, For a circle of radius R and central angle θ, chord length c = 2R sin(θ/2). Here: c = 10, θ = 120° ⇒ θ/2 = 60°. 10 = 2R sin 60° = 2R × (√3/2) = R√3 ⇒ R = 10/√3 cm.
More Geometry Questions
- In ΔABC, PQ is parallel to BC If AP: PB=1:2 and AQ=3 cm, AC is equal to?
- If O is the orthocentre of ΔABC , if ∠ BOC = 1250 then what is the measure of ∠ BAC?
- In ΔABC, D is a point on BC such that AD bisects ∠A. If BD = 6 cm, DC = 9 cm, find AB/AC.
- Find the difference between angle and its complement if the angle is two-seventh of its complement.
- AC and CE are the medians of triangle ABD and ACD respectively. If area of triangle ACE is 15 cm 2 , then find the area of triangle ABD.
- Let G be the centroid of the equilateral triangle ABC of perimeter 24 cm. Then the length of AG is
- The perimeter of a rectangle is 60 meters. If the length of the rectangle is twice the width, find the area of the rectangle.
- In triangle ABC, AB = AC. Point D lies on AB such that AD = DC = BC. Find the value of ∠BDC.
- Question 9
- If O is circumcentre of acute angled triangle ABC, if ∠ BOC = 150˚ then ∠ BAC = ?