Question
‘G’ has 35% fewer stickers than ‘H’. ‘H’ has
40% more stickers than ‘I’. By what percent are the stickers with ‘G’ less than those with ‘I’?Solution
ATQ,
Let, number of stickers with ‘H’ = 14s
Number of stickers with ‘G’ = 0.65 × 14s = 9.1s
Number of stickers with ‘I’ = (14s/1.4) = 10s
So, required percentage = {(10s – 9.1s)/10s} × 100 = 9%
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