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    Question

    ‘G’ has 35% fewer stickers than ‘H’. ‘H’ has

    40% more stickers than ‘I’. By what percent are the stickers with ‘G’ less than those with ‘I’?
    A 9% Correct Answer Incorrect Answer
    B 32% Correct Answer Incorrect Answer
    C 12% Correct Answer Incorrect Answer
    D 18% Correct Answer Incorrect Answer

    Solution

    ATQ,

    Let, number of stickers with ‘H’ = 14s

    Number of stickers with ‘G’ = 0.65 × 14s = 9.1s

    Number of stickers with ‘I’ = (14s/1.4) = 10s

    So, required percentage = {(10s – 9.1s)/10s} × 100 = 9%

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