Question
If median AD of an equilateral ∆ABC is 24 cm and G is
centroid. Find AG?Solution
Meeting point of all medians is called as centroid. Always remember that centroid divided median in 2:1 So here AG: GD = 2:1 & AD = 24 cm So dividing 24 into 2:1 , AG = 2/3 of AD = 2/3 of 24 = 16 cm
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (√ 484 – √ 256) = ?
(13)2 - 3127 ÷ 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 ÷ 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}
(15 × 225) ÷ (45 × 5) + 480 = ? + 25% of 1240
√ [? x 11 + (√ 1296)] = 16
11 × 25 + 12 × 15 + 14 × 20 + 15 = ?