Question

If in a ΔABC, the external angle bisector of angle A,

Here CD BD- BC 6 - 4 2cm, By External angle bisector theorem, AB AC BDCD 42

meets BC when extended at a point D, BD = 6cm , BC = 4 cm then what is AB:AC ?

A 1:3

B 3:2

C 4:2

D 2:3

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Solution