Question
In ∆ABC, AB = 5cm, BC = 10cm, and AC = 13cm then find
out the value of cos A.Solution
From the Cosine rule, we get. BC2 = AC2 + AB2 - 2AC.AB.cos A 100=25+169-2×5×13×Cos A 130CosA=194-100=94 cos A = 94/130 =47/65
More Geometry Questions
15, 23, 30, 36, 41, ?
7, 7, 14, 40, ?, 227
- What will come in place of (?) in the given number series.
1, 8, 27, ?, 125, 216 - What will come in place of the question mark (?) in the following series?
6, 6, 9, ?, 32, 56 5 6 15 40 89 170 ?
...7, 9, 21, ?, 107, 197
- What will come in place of (?) in the given number series.
7, 14, 28, 56, ?, 224 79 86 76 89 73 ?
...14 36 80 168 ? 696
7 29 61 ? 211 349
...
Relevant for Exams:
