Question
A man distributed some candies to his three sons A, B
and C. A, being the eldest got two times the number of candies that C got while A and B together have 62 candies. B and C have 20/33 times the number of candies that A and C together have. Find the number of candies that B has.Solution
A = 2C B + C = 20/33 (A + C) ∴B + C = 20/33 ( 2C + C ) ⇒B + C = 20/11C ⇒B = 9/11C Now, it’s given that A +B = 62 ∴2C + 9/11C = 62 31/11C = 62 ⇒C = 22 ⇒B = 9/11 X 22 = 18 candies
Statements: R ≥ S > T; U < V ≤ T; V > W
Conclusions:
I. R > V
II. W < S
III. T > W
Statements: A @ D % M % N; M $ P $ Q
Conclusions : I. D % Q I...
Statements: Q ≤ R < A; R ≥ N > S; S ≥ T > U
Conclusions:
I. A > N
II. U < N
III. S ≥ Q
Answer the questions based on the information given below.
A @ B means A is not smaller than B
A & B means A is neither smaller than nor...
Which of the following should be placed in the blank spaces respectively ( in the same order from left to right) in order to complete the given express...
Which of the following symbols respectively should replace the question marks in order to make the expression V ≥ M and X ≤ H definitely true?
<...If “M % N # O © P @ S © T $ W” is true then which of the following is definitely not true?
(i) M # P
(ii) O © T
(iii) N #...
Statement: L ≥ M ≤ R = S; M > N ≥ P
Conclusions: I. P ≤ M II. L > N
Statements:
A < B = C; D = E ≤ F ≤ G; E ≤ B
Conclusions:
I). G ≥ C
II). D ≤ B
III). C ≥ D
Statement: T>U<V<X=C>S ;U<P ≥X
I. T < P
II. P > S
