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Let f(x) =5a³–15a² +14a–3 … (1) Let (2a-2) =0 2a =2 a =2/2 a=1 put the value of ‘a’ in EQ (1). 5a³–15a² +14a–3 =5(1)3-15(1)2+14×1-3 =5 -15+14-3 = 19 -18 = 1
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