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To determine if the number 10293y8 is divisible by 11, we apply the divisibility rule for 11: Calculate the alternating sum and difference: S1-0-2-93-y+8 Simplifying- S=(1+2+3+8)-(0+9+y) S=14-9-у S=5-y For the number to be divisible by 11, S must be divisible by 11 or equal to 0. Therefore: 5- y = 0 (mod 11) y =5.
16% of 250 + 32% of 500 = ?
{5% of (20 × 25) + 6% of (30 ×35)} ÷ 11 = ?
Find the value of 5342.5 +543.45+54.345 +5.4345+0.54345.
181/8 + 51/4 – 63/8 = ? + 9/2
5.45% of 1854 – 37.5% of 1096 = ? – 48% of 630
12% of 10% of 15% of 5000 + (12 x 15) = ?
If 32x + 1– 3x= 3x + 3– 32, then values of x are:
√3598 × √(230 ) ÷ √102= ?
If 840 ÷ 12 + 1025 ÷ 25 - n + 45 × 4 = 960 ÷ 16 × 132 ÷ 44, then the value of n is:
The sum of two numbers is 16 and their product is 63. The sum of their reciprocal is equal to:
