At what time will a train reach city P from city Q?
Statement I: The 600 meter long train crosses a signal pole in 20 seconds.
Statement II: The another train crosses a 400 m long platform in 30 secs.
Statement III: The train leaves city P at 10:00 am for city Q situated at a distance of 1,620 km.
From I and III, Speed of the train = 600/20× 18/5 = 72 km/hr. Time = 1620/72 = 22*1/2 hrs. Arrival time = 10 am + 22*1/2hrs = 8.30 am. Statement I and III is sufficient to answer the question.
I. x2 - 20x + 96 = 0
II. y2 - 23y + 22 = 0
I. 49y2+ 35y + 6 = 0
II. 12x2+ 17 x + 6 = 0
I. 165x² + 97x + 10 = 0
II. 117y² - 163y + 56 = 0
I. 2x2– 25x + 33 = 0
II. 3y2+ 40y + 48 = 0
I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
I. 2x² + 11x + 12 = 0
II. 2y² + 19y + 45 = 0
I. 77x² - 25x – 72 = 0
II. 42y² + 13y – 42 = 0
I. 2y² - 3y – 14 = 0
II. 3x² - 7x + 4 = 0
I. (2x-3)3+ 1/((2x-3)³)=2
II. 4y²+(y+8)^2= 157
I. 2x2 + 3x - 9 = 0
II. 3y2 - y - 10 = 0
