Question
The quantity of water in vessel A is how much percent
more than the quantity of P1 in vessel B? Study the data carefully and answer the following questions: There are three types of mixtures in three different vessels A, B and C. The ratio of milk and water in vessel A is 5:2. The ratio of milk and P1 in vessel B is 2:1. The quantity of water in vessel C was equal to that of vessel A. If 28 litres of mixture from vessel A is taken out and poured in vessel B, then the quantity of milk in vessel B becomes 40 litres. If 40% of the mixture from vessel C is taken out then the quantity of P1 in vessel C becomes 15 litres. Ratio of quantities of mixture in B and C is 6:13. Note: P1 is soluble component. Vessel A, B and C do not contain P1, water and milk respectively.Solution
         Milk      Water      P1 A        5x           2x            - B        2y             -            y              C          -             2x Vessel A, => 5x + 2x = 28 => x = 4 Quantity of milk in vessel A = 5x = 20 Quantity of water in vessel A = 2x = 8 Quantity of milk in vessel B, => 2y + 20 = 40 => y = 10 litres Quantity of milk in vessel B = 20 litres Quantity of P1 in vessel C = (1500/60) = 25 litres Now, ratio of quantities of mixture in B and C is 6:13. => 30/C = 6/13 => C = 65 Quantity of mixture in C = 65 litres So, 2x + 25 = 65 => 2x = 40 litres Quantity of milk in vessel A = 40 litres Quantity of water in vessel A = 100 litres 
Required % = [(40 – 10)/10] x 100 = 300%
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