The number of boys in school C is approximately how much percent more than the number of teachers in school B?
Let the number of teachers in school A = 5x Then the number of boys in school A = 7x According to the question, => 5x + 7x = 84 × 2 => x = 14 So, number of teachers in school A = 5 × 14 = 70 Number of boys in school A = 7 × 14 = 98 Number of girls in school B = 84 × (9/7) = 108 Number of girls in school C = 140 – 108 = 32 Number of boys in school C = 98 + 2 = 100 Number of teachers in school B = 168 × (13/24) = 91 Number of boys in school B = 168 – 91 = 77 Number of teachers in school C = 91 + 11 = 102 Number of boys in school C = 98 + 2 = 100 Required % = [(100 – 91)/91]×100 = 10% approx.
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