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Start learning 50% faster. Sign in nowM is sitting 3rd to the left of the one who is sitting 2ndto the right of C. Here we get two possibilities. Only three persons are sitting between D and O. P is an immediate neighbor of either M or C. Person who is sitting opposite to A, is sitting 2ndto the right of O. Here we get two possibilities in both cases.
N is sitting 2nd to the right of B. N is neither sitting opposite to C nor sitting in the corner of the table. We cannot fix the position of N in case (1), case (1a) and case (2). So these cases are eliminated.
I. 6x2 – 7x - 20 = 0
II. 3y2 - y - 14 = 0
LCM of 'x' and 'y' is 30 and their HCF is 1 such that {10 > x > y > 1}.
I. 2p²- (x + y) p + 3y = 0
II. 2q² + (9x + 2) = (3x + y) q
I. 3x2 – 16x + 21 = 0
II. y2 – 13y + 42 = 0
I. 2x2– 5x – 63 = 0
II. 2y2– 7y – 72 = 0
I. x² – 44x + 468 = 0
II. y² – 30y + 216 = 0
I. 5x2 – 18x + 16 = 0
II. 3y2 – 35y - 52 = 0
(i) 2x² + 14x - 16 = 0
(ii) y² – y – 12 = 0
I. x2 + 91 = 20x
II. 10y2 - 29y + 21 = 0
I. x2 - 20x + 96 = 0
II. y2 - 23y + 22 = 0
I). p2 + 8p + 15 = 0
II). q2 + 9q + 20 = 0