Question
The speed of a boat in still water is 22 km/h and the
speed of the stream is 8 km/h. The boat first goes 60 km downstream and then travels upstream a distance which is x% less than the distance travelled downstream. If the total time taken for the entire trip is 5 hours, find the value of ‘x’.Solution
ATQ, Distance covered by boat in upstream = [{1 − (x/100)} × 60] km Upstream speed of the boat = 22 − 8 = 14 km/h Downstream speed of the boat = 22 + 8 = 30 km/h According to the question; [{{1 − (x/100)} × 60} / 14] + (60 / 30) = 5 Or, {1 − (x/100)} × (60/14) = 5 − 2 Or, {1 − (x/100)} × (60/14) = 3 Or, 1 − (x/100) = 3 × (14/60) Or, 1 − (x/100) = 42/60 Or, 1 − (x/100) = 7/10 Or, (x/100) = 1 − 7/10 = 3/10 Or, x = 30
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