Question
A boat covers (x – 20) km upstream in the same time it
covers (2x – 95) km downstream. If the speed of the boat and stream are 15 km/h and 3 km/h respectively, find the value of ‘x’.Solution
ATQ,
(x – 20)/(15 – 3) = (2x – 95)/(15 + 3)
(x – 20)/12 = (2x – 95)/18
18x – 360 = 24x – 1140
6x = 780 → x = 130
So, the value of ‘x’ is 130 km.
1242.12 ÷ √530 + 1139.89 ÷ 14.91 = ? + 45.39
? = 25.08 + 11.99 × 24.07
40 × 55.96 ÷ 7 – 20% of 699.81 + 63 = ? - (11479.50 ÷ 7)
25.902 × 78.095 + 999.996% of 200.08 + 20.005 % of 7999.997 = ? × 15.008 × 33.009
11.67 × 50.23 + ? = 14.88% of 600.44 + 9.66 × 8.272
78% of 1450 + 26² = ? + 1323 ÷ 17
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
65.22 of 359.98% + 459.99 ÷ 23.18 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
