Question
A man swims 2km/h against the stream and goes 1 km in 10
minutes along the stream, how much time will it take to cover 5 km in still water?Solution
Let the speed of boat in still water =B and speed of stream =S then – ATQ- B-S= 2km/h    … (1) B+S=1/10 km/minutes B+S=6 km/h Solving (1) +(2) 2B=3+6=8 B=8/2=4km/h Take the time cover 5 km in still water = 5/4 =5/4 h.
- What will come in place of (?), in the given expression.
√2025 + 35% of 400 = ? √(24 × 5 ÷ ?) × 4 = 56 + 34 – 10
(20% of 15% of 600 – 6) × 5 + 84 = ?2Â
(13)2 + 6 × (19)2 – 312 × 4 = ?
What will come in the place of question mark (?) in the given expression?
(18 × 8 ÷ 12) × 10 = ?
`sqrt(5476)` + 40% of 1640 = ? `xx` 4 - 2020
{(81% of 800 + 28 × 4) – 27 × ?} = 11 × 20
2(1/3) + 2(5/6) – 1(1/2) = ? – 6(1/6)
- What will come in the place of question mark (?) in the given expression?
(6/11) of 121 - ?% of 100 = 5² + 5 If x + y + 3 = 0, then find the value of x3 + y3 – 9xy + 9.