Question
Speed of a boat in still water is 15 kmph and speed of
stream is 12 kmph. A man rows to a place at a distance of 54 km and come back to starting point. The total time taken by him is:Solution
ATQ, For upstream(against the stream), the effective speed is (V-S), where V is the speed of boat = 15km/h S is the speed of the styream = 12km/h downstream speed (v+s)=15+12=27km/h Upstream speed(V-S) = 15 - 12 = 3km/h Now, Total time = [Distance/speed]Â Time = (54/27) +(54/3)Â time = 2+18 =20hoursÂ
Simplify the following expressionÂ
Â
`(256/6561)(1/4) = ?`
(60/15) × 25 + 15 2 – 18% of 200 = ? 2
[(7/8 of 640 - 60% of 300) × (√225 ÷ 5)] ÷ (1/4 of 800) = ?
25% of 60 × 15% of 120 = 30% of (?)
45% of 1020 + ?% of 960 = 747
- Find the simplified value of the given expression.
(-8) x {15 - (-4) x (-5)} (36/8)2 × (912/38) ÷ (122/1586) = ?
...5555 ÷ 11 ÷ 5 = 100 + ?
(30% of 400 - 20% of 540 + 35% of 1000) = ?