Question
The speed of the stream is 15 km/h. Boat βAβ covers
100 km distance against the stream in 4 hours and boat βBβ covers 90 km distance against the stream in 3 hours. The speed of boat βBβ in still water is how much percent of the speed of boat βAβ in still water?Solution
Speed of boat βAβ upstream = 100/4 = 25 km/h Speed of boat βBβ upstream = 90/3 = 30 km/h Speed of the boat βAβ in still water = 25 + 15 = 40 km/h Speed of the boat βBβ in still water = 30 + 15 = 45 km/h Required percentage = (45/40) Γ 100 = 112.5%
If B is coded = 4, D is coded = 8, and E is coded = 10, then what will be the code for J?
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