Question
X, Y and Z together can complete a work in 15 days. X
and Y together can complete the same work in 30 days. Z alone can finish the same work in how many days?Solution
Let us assume Z alone can complete the work in 'x' days The efficiency of X, Y, and Z = (1/15) The efficiency of X and Y = (1/30) The efficiency of Z = (1/x) = (1/30) + (1/x) = (1/15) By solving the value of 'x' ⇒ x = 30 days ∴ The required result will be 30 days.
What does the following code do?
x = [1, 2, 3]
y = [4, 5, 6]
z = x + y
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