Question
In a fixed time, a boy swims thrice the distance along
the current that he swims against the current. If the speed of the current is 10 km/hr, the speed of the boy in still water isSolution
Let the rate of swimming in still water be x km/hr Rate down-stream = (x + 10) km/hr Rate up-stream = (x – 10) km/hr According to the question, (x + 10) t = 3 (x – 10) × t x + 10 = 3x – 30 x = 20 km/hr
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