Question
There are three numbers a, b and c such that a = 160,
(a + b) = 460 and (c – b) = 80. Find their average.Solution
ATQ, Given, a = 160, (a + b) = 460 and (c – b) = 80 Therefore, b = 460 – 160 = 300 And, c = 300 + 80 = 380 Required average = (160 + 300 + 380)/3 = 280
What will come in the place of question mark (?) in the given expression?
? X √36 - 184 = 62 X 4
8 × 25% of ? = 400
√64 of √225 = √(25 + ?) X 12
3.3 Times 2/27 of 40% of 364=?
{(300 ÷ 15)% of 1500} ÷ 6 = ? + 120Â
{(5/8) + (4/5)} × (?/19) = 33
300% of (3341 – 471) = ? × (√4225/195)
1550 ÷ 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)     Â
What value should come in the place of (?) in the following questions?
(7/9) of (15/4) of 480 = ?
808 ÷ (128)1/7 + 482 = 4 × ? + 846