Question
There are three numbers a, b and c such that a = 160, (a +
b) = 460 and (c –
b) = 80. Find their average.
Solution
ATQ, Given, a = 160, (a + b) = 460 and (c – b) = 80 Therefore, b = 460 – 160 = 300 And, c = 300 + 80 = 380 Required average = (160 + 300 + 380)/3 = 280
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