Question
A bowler gives 16.2 runs per wicket. He gives 32 runs
and takes 8 wickets in a last match after which his average becomes 15.4 runs per wicket. How many wickets had been taken by him before the last match?Solution
Bowling average = (total runs conceded)/(total wicket taken ) Let the total number of wickets be x Then, bowling average = 16.2 Runs conceded = 16.2 x Now, (16.2 x + 32)/(x + 8)= 15.4 16.2 x + 32 = 15.4 (x + 8) 16.2 x + 32 = 15.4 x + 123.2 0.8 x = 123.2 - 32 x = 91.2/0.8 = 114 Alternate method: Using Allegation method, Average rate before last match Average in last match 16.2 32/8 = 4 Net Average = 15.4 Number of wickets before last match wickets in last match 11.4 : 0.8 114 : 8 Hence number of wickets before last match = 114
70.14% of 799.95 - 240.12 = ? + 40.17% of 299.95
33.33% of 809.891 + 66.66% of 212.91 = ?
(?)2 = (5.99)2 + (7.88)2 + 43.99
68.98 × 41.03 – (12.33)² + 15.78% of 8398.87 = ? – 40.22
124.88% of 1199.85 + 99.99 ÷ 3.99 = ?
(519.98 + ?) ÷ 13.01 = √440 + 20.0
(439.98 ÷ 10.99) × 23.98= ? × (23.98) 2 ÷ 47.98
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
41.97 × 5.12 ÷ 2.99 + 49.89 = ?× 1.99
?² x