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    Question

    What is the average of the squares of the first 19 natural

    numbers?
    A 122 Correct Answer Incorrect Answer
    B 126 Correct Answer Incorrect Answer
    C 130 Correct Answer Incorrect Answer
    D 134 Correct Answer Incorrect Answer

    Solution

    Sum of squares of first 'n' natural numbers = n ├Ч (n + 1) ├Ч (2n + 1) ├╖ 6
    So, average = n ├Ч (n + 1) ├Ч (2n + 1) ├╖ 6n = (n + 1) ├Ч (2n + 1) ├╖ 6
    = (19 + 1) ├Ч (2 ├Ч 19 + 1) ├╖ 6
    = 20 ├Ч 39 ├╖ 6
    = 130

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