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    Question

    What is the average of the squares of the first 29

    natural numbers?
    A 275 Correct Answer Incorrect Answer
    B 285 Correct Answer Incorrect Answer
    C 295 Correct Answer Incorrect Answer
    D 305 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Sum of squares of first 'n' natural numbers = n ├Ч (n + 1) ├Ч (2n + 1) ├╖ 6
    So, average = n ├Ч (n + 1) ├Ч (2n + 1) ├╖ 6n = (n + 1) ├Ч (2n + 1) ├╖ 6
    = (29 + 1) ├Ч (2 ├Ч 29 + 1) ├╖ 6
    = 30 ├Ч 59 ├╖ 6
    = 295

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