Question
What is the average of the squares of the first 29
natural numbers?Solution
Sum of squares of first 'n' natural numbers = n × (n + 1) × (2n + 1) ÷ 6
So, average = n × (n + 1) × (2n + 1) ÷ 6n = (n + 1) × (2n + 1) ÷ 6
= (29 + 1) × (2 × 29 + 1) ÷ 6
= 30 × 59 ÷ 6
= 295
W is taller than K who is shorter than U. O is taller than D but shorter than K. U is shorter than W. Who is the tallest?
Among F, G, H, I, J and K. H is taller than only F and K and I is shorter than only J and G. If each of them has a different height who among them will ...
What could be the possible height of R?
There are five persons Q, W, R, T and Y of different weights. T is heavier than Q and Y but not the heaviest. W is the lightest. Who among the following...
Who among the following weigh lighter than D?
In a group of four persons B, N, V, and W, V is fatter than only W but not as fat as N. B is also not as fat as N. Who is the leanest person in the group?
What is the weight of T?
There are five friends - D, F, H, M and P who have different heights. F is the tallest. H is taller than only M. P is not as tall as D. Who among the fo...
Who among the following is shorter than I but heavier than I?
Who is the second heaviest person?
Relevant for Exams:
