Question
The average of forty numbers is 45 while the average of
first twenty-two numbers and last twenty-two numbers is 50 and 60, respectively. Find the twenty-second term.Solution
ATQ,
Sum of forty numbers = (40 × 45) = 1800
Sum of the first twenty-two numbers = (22 × 50) = 1100
Sum of the last twenty-two numbers = (22 × 60) = 1320
So, twenty-second term = 1100 + 1320 - 1800 = 620
1930 1805 1589 1246 734 ?
...13Â Â Â Â Â Â Â Â Â Â 182Â Â Â Â Â Â Â Â 303Â Â Â Â Â Â Â Â 384Â Â Â Â Â Â Â Â 433Â Â Â Â Â Â Â Â ?
...2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 19Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 70...
6   16  ?     244  1,245  7,506  52,591
36, 49, 23, 62, ?, 75
24, 33, 50, ?, 108, 149
1. In series II, if ‘x’ is the right term, then find which of the following statement(s) are true.
I. x/124 is a factor 6 and 8.
Compute Σ (1 / (k(k+1))) from k = 1 to 10.
21, 22, 48, 153, 628, ?
157, 159, 189, 319, ‘?’, 1 407 , 2749 Â
Relevant for Exams:
