Question
The average of forty numbers is 45 while the average of
first twenty-two numbers and last twenty-two numbers is 50 and 60, respectively. Find the twenty-second term.Solution
ATQ,
Sum of forty numbers = (40 × 45) = 1800
Sum of the first twenty-two numbers = (22 × 50) = 1100
Sum of the last twenty-two numbers = (22 × 60) = 1320
So, twenty-second term = 1100 + 1320 - 1800 = 620
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
Find the approximate value of Question mark(?). No need to find the exact value.
24.95 × (36.06 ÷ 6) + 74.95% of 159.89 – √(143.94) × 2....
(18.31)2 – (13.68)2 + (2344.20 + 82.32) ÷ ? = 229.90
32.12% of 2399.98 + 64.04% of 2499.95 = ? × 15.95
(21.02 × 5.83 × 12.03 ÷ 6.99 of 4.03) + 31.93% of 50.03 = ?
20.22% of (61.9 × 5.01) + 69.97 =?
29.81 % of 49.91 + 14.28% of 147.09 + 179.91 = ?3
?² × 55% of (29 + 32 - 41) = 41.66% of 216 + 9
? = 28.04² ÷ (4.01⁵ + 9.89 × 20.20) + 84.56% of (198.76 × 30.03)
(10.98% of 499.99) - 4.998 = √?