Question
The average age of A, B, and C is 20 years. 3 years ago,
the sum of the ages of A and B was 7 more than that of C. Find the present age of C.Solution
A+B+C = 20×3=60 3 years before = A+B+C = 60-9 =51 SO, NOW ATQ- (A+B) +C=51 C+7+C = 51 2C =44 C= 22 So now the present age of C = 22+3=25 years
More Average Questions
- Determine the final value of this expression:
(1/5) of {5⁴ - 24 × 14 + 12 × 18 - 10.5 of 10²} 3% of 842 ÷ 2% of 421 = ?
√225 + 27 × 10 + ? = 320
- Determine the value of ‘p’ if p = √529 + √1444
45 % of 180 + √144 * 8 = ?2 + 70 % of 80
Determine the value of 'p' in following expression:
720 ÷ 9 + 640 ÷ 16 - p = √121 X 5 + 6²- 7?2 = √20.25 × 10 + √16 + 32
- What will come in place of the question mark (?) in the following questions?
(2⁴ + 6²) ÷ 2 = ? 18(1/3) + 9(2/3) – 10(1/3) = 1(2/3) + ?
Relevant for Exams:
