Question
The average age of A, B, and C is 20 years. 3 years ago,
the sum of the ages of A and B was 7 more than that of C. Find the present age of C.Solution
A+B+C = 20×3=60 3 years before = A+B+C = 60-9 =51 SO, NOW ATQ- (A+B) +C=51 C+7+C = 51 2C =44 C= 22 So now the present age of C = 22+3=25 years
More Average Questions
12.5% of (100 + ?) = 40
2/9 of 5/8 of 3/25 of ? = 40
24 × √? + 4008 ÷ 24 = 40% of 200 + 327
7(1/2) – 3(5/6) = ? − 2(7/12)
280 ÷ 14 + 11 × 12 – 15 × 6 = ?
1550 ÷ 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)
25% of 1000 + 10% of 150 – 22 × ? = 45
√ 729 × 5 – 220 % of 15 + ? = 120% of 160
What will come in the place of question mark (?) in the given expression?
(40% of ? × 43 ) – 232 = 751
180 % of 45 + √144 × 8 = ?2 + 80 % of 70
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