Question
The average age of A, B, and C is 20 years. 3 years ago, the sum of the ages of A and B was 7 more than that of
C. Find the present age of
C.
Solution
A+B+C = 20×3=60 3 years before = A+B+C = 60-9 =51 SO, NOW ATQ- (A+B) +C=51 C+7+C = 51 2C =44 C= 22 So now the present age of C = 22+3=25 yearsÂ
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