Question
An intern was paid a stipend of Rs. 1,792 for a period
of 30 days calculated on daily basis. During this period, he was absent for 4 days and was fined Rs. 12 per day for absence. He was given full amount for only 20 days as he was late for the rest of the days and he got only half of the amount on the late days. Had the intern come on time every day, not being absent on any day, what stipend he would have been received?Solution
Let the stipend per day of the intern be Rs. x He came late for 30-(20 +4) = 6 days Then, 20x [if gte msEquation 12]>
I). 5p2 Â - p - 4 = 0
II). q2 - 12q + 27 = 0
I. y/16 = 4/yÂ
II. x3 = (2 ÷ 50) × (2500 ÷ 50) × 42 × (192 ÷ 12)
I). p2 + 8p + 15 = 0
II). q2 + 9q + 20 = 0
I. 2x² + 11x + 12 = 0
II. 2y² + 19y + 45 = 0
I:Â x2Â - 33x + 242 = 0
II:Â y2Â - 4y - 77 = 0
I. 6x² - 23x + 7 = 0
II. 6y² - 29y + 9 = 0
I. 6x2 + 23x + 10 = 0
II. 2y2 - 3y - 5 = 0
I. 8/(21x) - 2/7 = 0
II. 16y² - 24y +9 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 4x² - 12x + 9 = 0
Equation 2: 2y² + 8y + 6 = 0