Question
In a gathering of 30 guests, the average age of each
guest in the class is 21 years. Later, 4 more guests join the party, causing the average age of the entire party to decrease by 12 months. Determine the average age of the 4 guests who joined the class.Solution
ATQ, Initial sum of ages of the guest in the party = 21 × 30 = 630 years New average age of the guest = 21 - (12/12) = 21 - 1 = 20 years New sum of ages of the guest in the party = 20 × 34 = 680 years So, the sum of ages of the guest who joined the party = 680 - 630 = 50 years So, the required average = (50/4) = 12.5 years
More Average Questions
(500 × 6 ÷ 10) - (√256 + 8) = ?
22% of 400 + √ ? = 34% of 800 - 25% of 400
(2/5)(32% of 4500 – 440) = ? × 8
1550 ÷ 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)
What will come in the place of question mark (?) in the given expression?
96 ÷ (9 - 6.6) + 17.5 X 6 = ? ÷ 8
13 X ? = 85 X 4 + √81 + 2
45% of 360 - 160 + ? = √324
((67)32 × (67)-18 / ? = (67)⁸
4567.89 - 567.89 - 678.89 = ?
82.3 × 644.7 × 723.4 × 815.85 = 72?
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