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ATQ, Initial sum of ages of the guest in the party = 21 × 30 = 630 years New average age of the guest = 21 - (12/12) = 21 - 1 = 20 years New sum of ages of the guest in the party = 20 × 34 = 680 years So, the sum of ages of the guest who joined the party = 680 - 630 = 50 years So, the required average = (50/4) = 12.5 years
The H.C.F. of two numbers is 22 and the other two factors of their L.C.M. are 9 and 11. The larger of the two numbers is:
Find the smallest 3-digit number that leaves 2 as remainder when divided by 6, 4 and 7.
What is the least number which when divided by 4, 6 & 8 leave a remainder 6 in each case & it is also divisible by 5?
The given numbers are in the ratio 2:5:6, and their highest common factor (HCF) is 15. Determine the least common multiple (LCM) of these numbers.
The LCM of two numbers is 5 times their HCF. The sum of LCM and HCF is 180. If one of the numbers is 150, then the other number is
The LCM of two numbers is 180, and the numbers are in the ratio 5:9. What will be the sum of the numbers?
Find the least number of four digits which is exactly divisible by 6, 24 and 32?
The least number which when divided by 3, 9, 27 and 81 leave remainder 2, 8, 26 and 80 respectively is?
The LCM of two numbers is 12 times their HCF. The sum of LCM and HCF is 403 and if both the number are smaller than their LCM. Find both the numbers?