Question
There are ‘x’ students in a class. Out of them
‘y’ are girls. The number of boys is 5 more than the number of girls. The sum of weight and the average weight of the girls is 506 kg and 46 kg, respectively. If 4 students are selected for a quiz competition then what will be the probability that the number of boys and the number of girls are equal?Solution
Total number of students = x The number of girls in the class = y The number of boys in the class = (y+5) Therefore the number of girls, => y = 506/46 = 11 Total number of girls = 11 Total number of boys = (11 + 5) = 16 Total number of students = (11 + 16) = 27 Required Probability = (11C2 × 16C2)/ 27C4 => (11 × 4)/117 = 44/117
Raju invests Rs. (p + 200) at a simple interest rate of 25% per annum for a period of 6 years and earns a total interest of Rs. (...
What approximate value should come in the place of question mark in the following questions?
1 ÷ 6.43 of 191.90 + 75.03% of 220 = ?² - 202.9
Find the approximate value of Question mark(?) for given equation.Â
(71.92% of 149.99) ÷ 12.04 + 107.98 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
1784.04 - 483.98 + 464.98 ÷ 15.06 = ?3
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will replace the question mark (?) in the following?
34.99...
6106.11 ÷ √? × 55.9 = 3976.21 Â
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
