Question
There are ‘x’ students in a class. Out of them
‘y’ are girls. The number of boys is 5 more than the number of girls. The sum of weight and the average weight of the girls is 506 kg and 46 kg, respectively. If 4 students are selected for a quiz competition then what will be the probability that the number of boys and the number of girls are equal?Solution
Total number of students = x The number of girls in the class = y The number of boys in the class = (y+5) Therefore the number of girls, => y = 506/46 = 11 Total number of girls = 11 Total number of boys = (11 + 5) = 16 Total number of students = (11 + 16) = 27 Required Probability = (11C2 × 16C2)/ 27C4 => (11 × 4)/117 = 44/117
Solve the following expression and calculate the approximate value.
398% of 388 + 129% of 323.89 – 430.93
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
156.76 + 14.08² + ?³ = √625.12 * 26.87
1299.999 ÷ 325.018 × 24.996 = ?
24.01 X 24.99 - ?% of 599.96 = 14.92 X 8.12
? = 782.24 + 1276.97 – 4.992
(9.013 – 15.04) = ? + 9.98% of 5399.98
Solve the given equation for ?. Find the approximate value.
[(49.88% of 320.11) × (34.85% of 460.24)] ÷ √783.94 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value....
