Question
A mixture of 140 lit contains milk and water where milk
is 20 lit more than water. If 28 lit mixture is taken out and 12 lit pure milk is added then ratio of milk and water becomes 39:R. Find value of R.Solution
Ratio of milk and water in the mixture = 80:60 = 4/3 Now, 28 liter of mixture is taken out and 12 liter pure milk is added so, ratio of milk and water becomes => (80 β 28Γ4/7) + 12/(60 β 28Γ3/7) = 39/R => 78/48 = 39/R => R = 24
564.932 + 849.029 β 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of βΉ60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to βΉ75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 Γ· 40.48 Γ 10.12 = ? Γ 2.16
(124.901) Γ (11.93) + 219.95 = ? + 114.891 Γ 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...