Question
If [x + (1/x)] = 3, find [x2 +
(1/x2)].Solution
ATQ, (x + 1/x)² = x² + 2 + 1/x² Given x + 1/x = 3 So 3² = x² + 2 + 1/x² 9 = x² + 1/x² + 2 x² + 1/x² = 9 - 2 = 7
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