Question
If (528 β 507 + 195) Γ· 11 + β1296 = x, then {(x/2)
+ 10} = ?Solution
ATQ,
(528 β 507 + 195) Γ· 11 + β1296 = x
(21 + 195) Γ· 11 + 36 = x
216 Γ· 11 + 36 = x
19.64 + 36 = x
x β 55.64
Therefore, {(x/2) + 10} β (27.82 + 10) = 37.82
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