Question
(3x × 9(x+1)) /
27(2x–1) = 1, then find 'x'.Solution
ATQ, → 9 = 3², 27 = 3³ → 3x × 3(2x+2) / 3(6x–3) = 1 → 3(–3x+5) = 1 → x = 5/3
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