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    Question

    (3x ├Ч 9(x+1)) /

    27(2xтАУ1) = 1, then find 'x'.
    A 2/5 Correct Answer Incorrect Answer
    B 5/3 Correct Answer Incorrect Answer
    C 3/7 Correct Answer Incorrect Answer
    D 8/9 Correct Answer Incorrect Answer

    Solution

    ATQ, тЖТ 9 = 3┬▓, 27 = 3┬│ тЖТ 3x ├Ч 3(2x+2) / 3(6xтАУ3) = 1 тЖТ 3(тАУ3x+5) = 1 тЖТ x = 5/3

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