Question
Solve for x: (2x − 1)/3 − (x − 4)/2 =
3Solution
ATQ, (2x − 1)/3 − (x − 4)/2 = 3 LCM(3,2) = 6 [2(2x − 1) − 3(x − 4)] / 6 = 3 2(2x − 1) = 4x − 2 3(x − 4) = 3x − 12 Numerator = (4x − 2) − (3x − 12) = 4x − 2 − 3x + 12 = x + 10 So (x + 10)/6 = 3 x + 10 = 18 x = 8
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