Question
3x +3y =10 and 3x+y =5
then find the value of 3x-y +3y-x.Solution
Given – 3x+y =5 3x +3y =10 (both side squaring) 32x +32y+2×3x×3y =100 32x +32y+2 ×3x+y =100            (Put the value of 3x+y) 32x +32y+2 ×5 =100 32x +32y =90   … (1) Then now- 3x-y +3y-x =3x/3y +3y/3x              (take LCM) = (32x +32y)/ (3x×3y) =90/5 =18.
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