Question
src="https://www.ixambee.com/questionimage/SSC-CHSL-Tier-1/1645785251-SSCCHSL001.png" alt="" />
Solution
Let x = √(56+√(56 +√(56+ √(56+√(56+)…∞ )))) x = √(56+x) Squaring both the sides, x² = 56 + x x² - x – 56 = 0 x² - 8x + 7x – 56 = 0 x(x-8) + 7(x + 7) = 0 x = 8 , -7 Alternate method: Split 56 in the product of two consecutive numbers i,e. 7 & 8 and the highest number is the answer. So answer is 8.
More Algebra Questions
What will come in place of (?) question mark in the given number series.
16, 24, 51, 115, 240, ?
Find the missing number in the given number series.
512, 128, 32, 8, ?, 171, 79, 88, 152, ?, 393
15, 31, 67, 131, ?, 375
1, 26, 75, 156, 277, ?
7 29 61 ? 211 349
...18   29   16   31   ?   33
72, 82, 62, 102, 22, ?
?, 15, 45, 225, 1575, 14175
166    156    136   ?     66    16
Relevant for Exams:
